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\text{2: chẵn},\; \text{3: tổng CS}\vdots 3,\; \text{5: tận 0,5},\; \text{9: tổng CS}\vdots 9a \cdot b = \text{ƯCLN}(a,b) \cdot \text{BCNN}(a,b)\frac{a}{b} + \frac{c}{d} = \frac{ad + bc}{bd}\frac{a}{b} \times \frac{c}{d} = \frac{ac}{bd}\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}p\% = \frac{p}{100}S = a \times bP = 2(a + b)S = a^2V = a \times b \times cV = a^3\frac{a}{b} = \frac{c}{d} \Leftrightarrow ad = bc\frac{a}{b} = \frac{c}{d} = \frac{a+c}{b+d} = \frac{a-c}{b-d}y = kx\;(k \ne 0)xy = k\;(k \ne 0)\hat{A} + \hat{B} + \hat{C} = 180°|a - b| < c < a + ba^2 + b^2 = c^2\text{c.c.c},\; \text{c.g.c},\; \text{g.c.g}ax^2 + bx + c = a(x - x_1)(x - x_2)\frac{A}{B} + \frac{C}{D} = \frac{AD + BC}{BD}ax + b = 0 \Rightarrow x = -\frac{b}{a}\;(a \ne 0)S = a \times hS = \frac{1}{2}(a + b) \times hS = \frac{1}{2}d_1 \times d_2\frac{a'}{a} = \frac{b'}{b} = \frac{c'}{c} = k\sqrt{a^2} = |a|\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}\;(a,b \ge 0)\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}\;(a \ge 0, b > 0)\begin{cases} ax+by=e \ cx+dy=f \end{cases}y = ax + b\;(a \ne 0)ax^2 + bx + c = 0\;(a \ne 0)\sin A = \frac{\text{đối}}{\text{huyền}},\; \cos A = \frac{\text{kề}}{\text{huyền}},\; \tan A = \frac{\text{đối}}{\text{kề}}l = \frac{\pi R n}{180}S = \frac{\pi R^2 n}{360}\hat{\text{nội tiếp}} = \frac{1}{2}\hat{\text{cung bị chắn}}(a+b)^2 = a^2 + 2ab + b^2(a-b)^2 = a^2 - 2ab + b^2a^2 - b^2 = (a-b)(a+b)(a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3(a-b)^3 = a^3 - 3a^2b + 3ab^2 - b^3a^3 + b^3 = (a+b)(a^2 - ab + b^2)a^3 - b^3 = (a-b)(a^2 + ab + b^2)\Delta = b^2 - 4acx = \frac{-b \pm \sqrt{\Delta}}{2a}\Delta' = b'^2 - ac \;(b=2b')x_1 + x_2 = -\frac{b}{a}x_1 \cdot x_2 = \frac{c}{a}x_1^2 + x_2^2 = S^2 - 2Pf(x)=ax^2+bx+c,\; a>0:\; f(x)\ge 0 \;\forall x \Leftrightarrow \Delta \le 0\frac{a+b}{2} \ge \sqrt{ab} \;(a,b \ge 0)|a+b| \le |a| + |b|x = \frac{D_x}{D},\; y = \frac{D_y}{D},\; D \ne 0\begin{cases} a_1x+b_1y=c_1 \ a_2x+b_2y=c_2 \end{cases}\vec{a}+\vec{b} = (a_1+b_1,\; a_2+b_2)\vec{a} \cdot \vec{b} = a_1 b_1 + a_2 b_2 = |\vec{a}||\vec{b}|\cos\thetaAB = \sqrt{(x_B-x_A)^2 + (y_B-y_A)^2}M = \left(\frac{x_A+x_B}{2},\; \frac{y_A+y_B}{2}\right)\sin^2 x + \cos^2 x = 1\tan x = \frac{\sin x}{\cos x},\; \cot x = \frac{\cos x}{\sin x}1 + \tan^2 x = \frac{1}{\cos^2 x}\sin(a \pm b) = \sin a \cos b \pm \cos a \sin b\cos(a \pm b) = \cos a \cos b \mp \sin a \sin b\tan(a \pm b) = \frac{\tan a \pm \tan b}{1 \mp \tan a \tan b}\sin 2x = 2\sin x \cos x\cos 2x = \cos^2 x - \sin^2 x = 2\cos^2 x - 1 = 1 - 2\sin^2 x\tan 2x = \frac{2\tan x}{1 - \tan^2 x}\cos^2 x = \frac{1 + \cos 2x}{2}\sin^2 x = \frac{1 - \cos 2x}{2}2\sin a \cos b = \sin(a+b) + \sin(a-b)\sin a + \sin b = 2\sin\frac{a+b}{2}\cos\frac{a-b}{2}\sin x = \sin \alpha \Leftrightarrow x = \alpha + k2\pi \;\text{hoặc}\; x = \pi - \alpha + k2\pi\cos x = \cos \alpha \Leftrightarrow x = \pm \alpha + k2\pi\tan x = \tan \alpha \Leftrightarrow x = \alpha + k\piA_n^k = \frac{n!}{(n-k)!}C_n^k = \frac{n!}{k!(n-k)!}(a+b)^n = \sum_{k=0}^{n} C_n^k a^{n-k} b^kP(A) = \frac{|A|}{|\Omega|}P(A \cup B) = P(A) + P(B) - P(A \cap B)P(\bar{A}) = 1 - P(A)P(X=k) = C_n^k \cdot p^k \cdot (1-p)^{n-k}u_n = u_1 + (n-1)dS_n = \frac{n(u_1 + u_n)}{2} = \frac{n[2u_1 + (n-1)d]}{2}u_n = u_1 \cdot q^{n-1}S_n = u_1 \cdot \frac{1-q^n}{1-q}\;(q \ne 1)S_\infty = \frac{u_1}{1-q}\;(|q|<1)\lim_{x \to 0} \frac{\sin x}{x} = 1\lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n = e\lim_{x \to 0} \frac{e^x - 1}{x} = 1\lim_{x \to 0} \frac{\ln(1+x)}{x} = 1(x^n)' = nx^{n-1}(\sin x)' = \cos x(\cos x)' = -\sin x(\tan x)' = \frac{1}{\cos^2 x}(\cot x)' = -\frac{1}{\sin^2 x}(e^x)' = e^x(a^x)' = a^x \ln a(\ln x)' = \frac{1}{x}(\log_a x)' = \frac{1}{x \ln a}(uv)' = u'v + uv'\left(\frac{u}{v}\right)' = \frac{u'v - uv'}{v^2}[f(u)]' = f'(u) \cdot u'a^m \cdot a^n = a^{m+n}a^m \div a^n = a^{m-n}(a^m)^n = a^{mn}\log_a(xy) = \log_a x + \log_a y\log_a\frac{x}{y} = \log_a x - \log_a y\log_a x^n = n \log_a x\log_a b = \frac{\ln b}{\ln a} = \frac{\log_c b}{\log_c a}\int x^n \, dx = \frac{x^{n+1}}{n+1} + C \;(n \ne -1)\int \frac{1}{x} \, dx = \ln|x| + C\int e^x \, dx = e^x + C\int \sin x \, dx = -\cos x + C\int \cos x \, dx = \sin x + CS = \int_a^b |f(x)| \, dxV = \pi \int_a^b [f(x)]^2 \, dx\int u \, dv = uv - \int v \, duz = a + bi \;(a,b \in \mathbb{R},\; i^2 = -1)|z| = \sqrt{a^2 + b^2}\bar{z} = a - bi,\; z \cdot \bar{z} = |z|^2a^2 + b^2 = c^2S = \frac{1}{2}ahS = \frac{1}{2}ab\sin CS = \sqrt{p(p-a)(p-b)(p-c)}\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = 2Ra^2 = b^2 + c^2 - 2bc\cos AS = \pi r^2C = 2\pi rV = S_{đáy} \cdot hV = \frac{1}{3}S_{đáy} \cdot hV = \pi r^2 hS_{xq} = 2\pi r hV = \frac{1}{3}\pi r^2 hS_{xq} = \pi r lV = \frac{4}{3}\pi r^3S = 4\pi r^2AB = \sqrt{(x_B-x_A)^2 + (y_B-y_A)^2 + (z_B-z_A)^2}M = \left(\frac{x_A+x_B}{2}, \frac{y_A+y_B}{2}, \frac{z_A+z_B}{2}\right)ax + by + cz + d = 0d(M, \alpha) = \frac{|ax_0 + by_0 + cz_0 + d|}{\sqrt{a^2+b^2+c^2}}\frac{x-x_0}{a} = \frac{y-y_0}{b} = \frac{z-z_0}{c}(x-a)^2 + (y-b)^2 + (z-c)^2 = R^2\vec{a} \times \vec{b} = \begin{vmatrix} \vec{i} & \vec{j} & \vec{k} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix}\cos(\alpha, \beta) = \frac{|a_1 a_2 + b_1 b_2 + c_1 c_2|}{\sqrt{a_1^2+b_1^2+c_1^2}\sqrt{a_2^2+b_2^2+c_2^2}}d = \frac{|[\vec{u_1}, \vec{u_2}] \cdot \vec{M_1 M_2}|}{|\vec{u_1} \times \vec{u_2}|}ax + by + c = 0y = kx + m\frac{x - x_1}{x_2 - x_1} = \frac{y - y_1}{y_2 - y_1}d(M_0, \Delta) = \frac{|ax_0 + by_0 + c|}{\sqrt{a^2 + b^2}}\tan \alpha = \left|\frac{k_1 - k_2}{1 + k_1 k_2}\right|d_1 \parallel d_2 \Leftrightarrow \frac{a_1}{a_2} = \frac{b_1}{b_2} \ne \frac{c_1}{c_2}d_1 \perp d_2 \Leftrightarrow a_1 a_2 + b_1 b_2 = 0(x-a)^2 + (y-b)^2 = R^2x^2 + y^2 - 2ax - 2by + c = 0\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\;(a > b > 0)(x_0 - a)(x - a) + (y_0 - b)(y - b) = R^2\bar{x} = \frac{x_1 + x_2 + \ldots + x_n}{n}\bar{x} = \frac{\sum n_i x_i}{\sum n_i}S^2 = \frac{1}{n}\sum_{i=1}^{n}(x_i - \bar{x})^2S = \sqrt{S^2} = \sqrt{\frac{1}{n}\sum(x_i - \bar{x})^2}M_e = x_{(n+1)/2}\;\text{(n lẻ)}M_o = \text{giá trị xuất hiện nhiều nhất}R = x_{max} - x_{min}Q_1,\; Q_2 (= M_e),\; Q_3r = \frac{\sum(x_i-\bar{x})(y_i-\bar{y})}{\sqrt{\sum(x_i-\bar{x})^2 \cdot \sum(y_i-\bar{y})^2}}\hat{y} = ax + bf'(x) > 0 \;\forall x \in (a,b) \Rightarrow f \nearrowf'(x_0) = 0,\; f'\text{ đổi dấu qua } x_0f''(x_0) = 0,\; f''\text{ đổi dấu}\lim_{x \to \pm\infty} f(x) = L \Rightarrow y = L\lim_{x \to a} f(x) = \pm\infty \Rightarrow x = ay = ax^3 + bx^2 + cx + d\;(a \ne 0)y = \frac{ax+b}{cx+d}\;(c \ne 0, ad-bc \ne 0)y - y_0 = f'(x_0)(x - x_0)