How to solve this physics problem about ac_circuit?

1. 📐 RLC电路: R=120Ω, L=13/100H, C=23F 2. 🔢 电抗: XL = ωL = 110.2699021 Ω, XC = 1/(ωC) = 0.00005125763063 Ω

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解题 RLC串联交流电路中 R = 120 Ω, L = 0.13 H, C = 23 μF，频率 f = 135 Hz。求阻抗Z和功率因数。 — 详细解答步骤 — Detailed Solution | AhaStep

Home›Physics›解题 RLC串联交流电路中 R = 120 Ω, L = 0.13 H, C = 23 μF，频率 f = 135 Hz。求阻抗Z和功率因数。 — 详细解答步骤

⚛️ PhysicsLevel 7 — 🔵 Intermediateac_circuit👁 20 views⏱ 1 min read

解题 RLC串联交流电路中 R = 120 Ω, L = 0.13 H, C = 23 μF，频率 f = 135 Hz。求阻抗Z和功率因数。 — 详细解答步骤

📝 Problem

RLC串联交流电路中 R = 120 Ω, L = 0.13 H, C = 23 μF，频率 f = 135 Hz。求阻抗Z和功率因数。

1. 📐 RLC电路: R=120Ω, ,

2. 🔢 电抗: XL = ωL = 110.2699021 Ω, XC = 1/(ωC) = 0.00005125763063 Ω

3. 📊 阻抗: = $\sqrt(120^{2} + (110.2698509)^{2}) = 162.9706723$ Ω

4. 📐 相位角: φ = arctan((XL-XC)/R) = 42.58038222°

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1. 📐 RLC电路: R=120Ω, ,

2. 🔢 电抗: XL = ωL = 110.2699021 Ω, XC = 1/(ωC) = 0.00005125763063 Ω

3. 📊 阻抗: = $\sqrt(120^{2} + (110.2698509)^{2}) = 162.9706723$ Ω

4. 📐 相位角: φ = arctan((XL-XC)/R) = 42.58038222°

🔒 4 steps remaining