How to solve this physics problem about ac_circuit?

1. 📐 RLC Circuit: R=10Ω, L=1/4H, C=83F 2. 🔢 Reactances: XL = ωL = 1478.119344 Ω, XC = 1/(ωC) = 0.000002037757104 Ω

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Solve In an RLC series AC circuit with R = 10 Ω, L = 0.25 H, C = 83 μF, f = 941 Hz.... — Step-by-Step Solution by AhaStep | AhaStep

Home›Physics›Solve In an RLC series AC circuit with R = 10 Ω, L = 0.25 H, C = 83 μF, f = 941 Hz.... — Step-by-Step Solution by AhaStep

⚛️ PhysicsLevel 4 — 🟢 Basicac_circuit👁 21 views⏱ 1 min read

Solve In an RLC series AC circuit with R = 10 Ω, L = 0.25 H, C = 83 μF, f = 941 Hz.... — Step-by-Step Solution by AhaStep

📝 Problem

In an RLC series AC circuit with R = 10 Ω, L = 0.25 H, C = 83 μF, f = 941 Hz. Find the impedance Z and power factor.

1. 📐 RLC Circuit: R=10Ω, ,

2. 🔢 Reactances: XL = ωL = 1478.119344 Ω, XC = 1/(ωC) = 0.000002037757104 Ω

3. 📊 Impedance: = $\sqrt(10^{2} + (1478.119341)^{2}) = 1478.153168$ Ω

4. 📐 Phase Angle: φ = arctan((XL-XC)/R) = 89.61237971°

🔒 4 steps remaining

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1. 📐 RLC Circuit: R=10Ω, ,

2. 🔢 Reactances: XL = ωL = 1478.119344 Ω, XC = 1/(ωC) = 0.000002037757104 Ω

3. 📊 Impedance: = $\sqrt(10^{2} + (1478.119341)^{2}) = 1478.153168$ Ω

4. 📐 Phase Angle: φ = arctan((XL-XC)/R) = 89.61237971°

🔒 4 steps remaining