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Solve: biquadratic x^4 + -19x^2 + 47 = 0 — Detailed Solution | AhaStep

Home›Math›Solve: biquadratic x^4 + -19x^2 + 47 = 0

📐 MathLevel 2 — 🟢 Basiccubic👁 17 views⏱ 1 min read

Solve: biquadratic x^4 + -19x² + 47 = 0

📝 Problem

biquadratic x^4 + -19x^2 + 47 = 0

✨Detailed Solution

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1

1. 📐 Cubic Equation: 0x^{2} + 0x + 0$ = 0$

2

2. 🔄 Reduce: t^{3} + (0)t + (0) = 0$

3

3. Δ ≈ 0: Repeated root

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4. x =: x = 0

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