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Solve: a_n = 4a_{n-1} + 0, a_0=5 — Detailed Solution | AhaStep

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📐 MathLevel 2 — 🟢 Basicrecurrence👁 15 views⏱ 1 min read

Solve: a_n = 4a₍n-1₎ + 0, a_0=5

📝 Problem

a_n = 4a_{n-1} + 0, a_0=5

✨Detailed Solution

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1

1. Type: First-order non-homogeneous

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2. Homogeneous: C·(4)ⁿ

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3. Particular: 0

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4. Solution: aₙ = 5·(4)ⁿ + 0

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