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Solve: a_n = 2a_{n-1} + 2, a_0=4 — Detailed Solution | AhaStep

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📐 MathLevel 2 — 🟢 Basicrecurrence👁 14 views⏱ 1 min read

Solve: a_n = 2a₍n-1₎ + 2, a_0=4

📝 Problem

a_n = 2a_{n-1} + 2, a_0=4

✨Detailed Solution

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1

1. Type: First-order non-homogeneous

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2. Homogeneous: C·(2)ⁿ

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3. Particular: -2

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4. Solution: aₙ = 6·(2)ⁿ + -2

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