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Giải: trùng phương x^4 + -18x^2 + 38 = 0 — Detailed Solution | AhaStep

Home›Math›Giải: trùng phương x^4 + -18x^2 + 38 = 0

📐 MathLevel 2 — 🟢 Basiccubic👁 16 views⏱ 1 min read

Giải: trùng phương x^4 + -18x² + 38 = 0

📝 Problem

trùng phương x^4 + -18x^2 + 38 = 0

✨Detailed Solution

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1. 📝 Nhận dạng: PT trùng phương: 18x^{2} + 38$ = 0$

2

2. 🔄 Đặt ẩn phụ: Đặt (ĐK:

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PT trở thành: 18t + 38$ = 0$

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3. 📐 Biệt thức: = (-18)² - 4·1·38 = 172

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