Skip to main content

✦Đang tải AhaStep...

🏠Home 📝Exam 📖Practice 🧩Kids Math🔑Sign In

Giải: trùng phương x^4 + -10x^2 + 22 = 0 — Detailed Solution | AhaStep

Home›Math›Giải: trùng phương x^4 + -10x^2 + 22 = 0

📐 MathLevel 2 — 🟢 Basiccubic👁 15 views⏱ 1 min read

Giải: trùng phương x^4 + -10x² + 22 = 0

📝 Problem

trùng phương x^4 + -10x^2 + 22 = 0

✨Detailed Solution

🔗 Similar Problems

Solve Solve: x^4 + -15x² + 38 = 0 — Step-by-Step Solution by AhaStep

Solve Solve the quadratic equation: x² + x + 2 = 0 — Step-by-Step Solution by AhaStep

Solve: x^4 + -14x² + 47 = 0

Solve Solve the quadratic equation: 11x² - 32x - 53 = 0 — Step-by-Step Solution by AhaStep

Solve Solve the quadratic equation: 4x² - 28x - 106 = 0 — Step-by-Step Solution by AhaStep

📚 Related Knowledge

Learn more about cubic in Math to master fundamental and advanced concepts.

📐 View cubic Theory →

📚 Solutions Library 📐 More Math 📖 Topic: cubic

🚀

Solve Your Problem

Take a photo or type your problem — AI solves step by step

1

1. 📝 Nhận dạng: PT trùng phương: 10x^{2} + 22$ = 0$

2

2. 🔄 Đặt ẩn phụ: Đặt (ĐK:

3

PT trở thành: 10t + 22$ = 0$

4

3. 📐 Biệt thức: = (-10)² - 4·1·22 = 12

🔒 5 steps remaining

Solve Solve the quadratic equation: 2x² - 23x + 48 = 0 — Step-by-Step Solution by AhaStep