How to solve this math problem about Algebra?

Let $t = x^2 - 3x$. The equation transforms into $t^2 - 2t - 8 = 0$. Factoring, we get $(t-4)(t+2) = 0$, which yields $t=4$ or $t=-2$. Case 1: $x^2 - 3x = 4 \Rightarrow x^2 - 3x - 4 = 0$. Factoring, $(x-4)(x+1) = 0$, so $x=4$ or $x=-1$.

Grade 10 Algebra: Solve Quadratic-Like Equations via Substitution — Detailed Solution

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Grade 10 Algebra: Solve Quadratic-Like Equations via Substitution — Detailed Solution | AhaStep

Grade 10 Algebra: Solve Quadratic-Like Equations via Substitution

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